1.

If eis thecharge of an electron in esu m is the mass in grams and v the voltage 'h' is the planck constant in erg sec then the wavelength of the electron in cm is

Answer»

`H//sqrt(Ve)`
`hsqrt(Vme)`
`hsqrt(Ve)`
`hsqrt(2mVe)`

SOLUTION :KINETIC energy of electrons = Potential energy GAINED by each ELECTRON
i.e., 1/2 m `upsilon^2=eV` or `upsilon=sqrt((2eV)/m)`
`therefore lambda=h/(m upsilon)=h/(m((2eV)/m)^(1//2))=h/sqrt(2mVe)`


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