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If emf of standard cell during cell reaction is 0.295 V at 298 K and n=2, then what is the equilibrium constant of such reaction ? [F=96500," "R=8.314KJ^(-1)mol^(-1)]

Answer»

`4.0xx10^(12)`
`1.0xx10^(2)`
`1.0xx10^(10)`
`2.0xx10^(11)`

Solution :`LOGK=(NF)/(0.059)`
`THEREFORE logK=(2xx0.295)/(0.059)=10`
`therefore K=1xx10^(10)`.


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