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If energy `(E )` , velocity `(V)` and time `(T)` are chosen as the fundamental quantities , the dimensions formula of surface tension will beA. `[EV^(-2)T^(-1)]`B. `[EV^(-1)T^(-2)]`C. `[EV^(-2)T^(-2)]`D. `[E^(-2)V^(-1)T^(-3)]` |
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Answer» Correct Answer - c Let surface tension `[e] = [E^(x)V^(y)T^(z)]` we have `[x] = [MT^(-2)]` `[E] = [ML^(2)T^(-2)], [V] = [LT^(-1)] and [T] = [T]` `rArr [S] = [ML^(2)T^(-2)]^(x) [LT^(-1)]^(y) [T]^(z)` `[M^(1)L^(0)T^(-2)] = [M^(x)L^(2x +y)T^(-2x -y +z)]` `x = 1` `2x + y = 0 rArr y = -2` `-2x - y + z = -2` `rArr -2 xx 1 - (-2) + z = -2` `rArr z = -2` Hence `[s] = [EV^(-2)T^(-2)]` |
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