1.

If eneryg E, velocity v and time t are taken t are taken as the fundamental units, what is the dimensional formula of intensity of radiation?

Answer»

`Ev^(-2)t^(-3)`
`Ev^(-1)t^(-1)`
`Ev^(-1)t^(-2)`
`Ev^(-2)t^(-2).`

Solution :Here INTENSITY `I`= ENERGY PER sec. per unit area.
`ML^(0)T^(-3)=E^(a)v^(B)t^(c )`
`=[ML^(2)T^(-2)]^(a)[LT^(-1)]^(b)[T]^(c )=M^(a)L^(2a+b)T^(-2a-b+c)`
`:.a=1`
`2a+b=0`
`b=-2a=-2`
`-2a-b+c=-3`
`-2+2+c=-3`
`c=-3`
`:.I=Ev^(-2)t^(-3).`
Hence correct choice is `(a)`


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