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If equation `(lamda^(2)-5lamda+6)x^(2)+(lamda^(2)-3lamda+2)x+(lamda^(2)-4)=0` is satisfied by more than two values of `x`, find the parameter `lamda`. |
Answer» If an equation of degree to is satisfied by more than two values of unknown, then it must be an identity. Then, we must have `lamda^(2)-5lamda+6=0,lamda^(2)-3lamda+2=0lamda^(2)-4=0` `implieslamda=2,3` and `lamda=2,1` and `lamda=2,-2` Common value of `lamda` which satisfies each condition is `lamda=2`. |
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