1.

If equilibrium constant K is 10^(3), the Delta G^(theta) for the reaction at 300 K is (assume R = 8.314 JK^(-1) mol^(-1)) :

Answer»

`- 16.582 KJ`
16.582 kJ
165.82 kJ
1658.2 kJ

Solution :`Delta G^(@) = -2.303 RT log K`
`= -2.303 x 8 XX 300 xx log 10^(3)`
`= -2.303 xx 8 xx 300 xx 3 = -16.582 kJ`


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