1.

If equivalent conductance of 1 M benzoic acid is 12.8 ohm^(-1) cm^(2) and if the conductance of benzoic ion and H^(+) ion are 42 and 288.42 ohm^(-1) respectively, its degree of dissociation is

Answer»

0.39
0.039
0.0035
0.00039

Solution :`(^^_(C_(6)H_(5)COOH)^(@))=lambda_(C_(6)H_(5)COO^(-))^(@)+lambda_(H^(+))^(@)`
`=42+288.42=330.42`
`alpha=(^^_( m)^(@))/(^^_( m)^(@))=(12.8)/(330.42)= 0.03 9=3.0%`


Discussion

No Comment Found

Related InterviewSolutions