1.

If equlibrium constnats of reaction, N_(2)+O_(2)hArr 2NO is K_(1) and 1/2N_(2)+1/2O_(2)hArrNO is K_(2), then

Answer»

`K_(1)=K_(2)`
`K_(2)=sqrtK_(1)`
`K_(1)=2K_(2)`
`K_(1)=1/2K_(2)`

SOLUTION :`N_(2)+O_(2)hArr2NO""...(i)`
`1/2N_(2)+1/2O_(2)hArrNO""...(ii)`
From equation NUMBER (i)
`K_(1)=([NO]^(2))/([N_(2)][O_(2)])""...(iii)`
For equation number (ii)
`K_(2)=([NO])/([N_(2)]^(1//2)[O_(2)]^(1//2))""...(IV)`
From equation (iii) & (iv) it is clear that
`K_(2)=(K_(1))^(1//2)=sqrt(K_(1)),"""Hence",K_(2)sqrt(K_(1))`


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