If ethanol and chloroform are present in a molar ratio of 2:3 then what is the vapor pressure at 20° C if vapor pressures of pure liquids are 5.95 kPa and 21.17 kPa, respectively?(a) 16.692 kPa(b) 15.082 kPa(c) 8.731 kPa(d) 12.038 kPaI got this question in an interview for internship.My question is taken from Vapour Pressure of Liquid Solutions topic in chapter Solutions of Chemistry – Class 12

If ethanol and chloroform are present in a molar ratio of 2:3 then wha

1.	If ethanol and chloroform are present in a molar ratio of 2:3 then what is the vapor pressure at 20° C if vapor pressures of pure liquids are 5.95 kPa and 21.17 kPa, respectively?(a) 16.692 kPa(b) 15.082 kPa(c) 8.731 kPa(d) 12.038 kPaI got this question in an interview for internship.My question is taken from Vapour Pressure of Liquid Solutions topic in chapter Solutions of Chemistry – Class 12
Answer» The correct answer is (b) 15.082 kPa Easy EXPLANATION: GIVEN, P^0eth = 5.95 kPa P^0chl = 21.17 kPa Mole ratio of ethanol ∶ CHLOROFORM = 2 ∶ 3 Total number of parts = 2 + 3 = 5 Therefore, mole fraction of ethanol, Xeth = 2/5 = 0.4 Mole fraction of chloroform, Xchl = 3/5 = 0.6 From Raoult’s law, pA = p^0A X XA Peth = 5.95 x 0.4 = 2.38 kPa Pchl = 21.17 x 0.6 = 12.702 kPa From Dalton’s law, Ptotal = Peth + Pchl Ptotal = 2.38 + 12.702 = 15.082 kPa.

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