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If excess of `NH_(4)OH` is added to `CuSO_(4)` solution, it forms blue coloured complex which isA. `Cu (NH_(3))_(4) SO_(4)`B. `Cu(NH_(3))_(2)SO_(4)`C. `Cu (NH_(4))_(4) SO_(4)`D. `Cu (NH_(4))_(2)SO_(4)` |
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Answer» Correct Answer - A `CuSO_(4) + 4NH_(4)OH rarr underset(Blue)([Cu(NH_(3))_(4)]SO) + 4H_(2)O` |
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