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If f^(11)(x)lt0(gt0) on an interval (a,b) then the curve y=f(x) on this interval is convex (concave) i.e it is below (above) any of its tangent lines If f^(11)(x_(0))=0 or does not exist and the second derivative changes sign when passing through the point x_(0) then the point (x_(0),f(x))is the = point of inflection of the curve y=f(x) y=x^(4)+ax^(3)+(3)/(2)x^(2)+1 is concave along the entire number scale then |
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Answer» `|a||ge1` |
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