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If f:A → N, A = {500, 1000, 1300, 1400}, f(x) = \(\sqrt{5600−4x}\), XER then find the value of f(x) for x = 1000. Also, for which value of x, f(x) = 20? |
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Answer» f(x)= \(\sqrt{5600−4x}\) Putting x = 1000, f(4)= \(\sqrt{5600−4(1000)}\) = \(\sqrt{5600−4000}\) = \(\sqrt{1600}\) =40 f(x) = 20 ∴ 20 = \(\sqrt{5600−4x}\) ∴ 400 = 5600 – 4x 4x = 5200 (20)2 = 5600 – 4x ∴ 4x = 5600 – 400 ∴ x = 1300 Hence, when x = 1300. then f(x) = 20. |
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