1.

If f:A → N, A = {500, 1000, 1300, 1400}, f(x) = \(\sqrt{5600−4x}\), XER then find the value of f(x) for x = 1000. Also, for which value of x, f(x) = 20?

Answer»

f(x)= \(\sqrt{5600−4x}\)

Putting x = 1000,

f(4)= \(\sqrt{5600−4(1000)}\)

\(\sqrt{5600−4000}\)

\(\sqrt{1600}\) =40

f(x) = 20

∴ 20 = \(\sqrt{5600−4x}\)

∴ 400 = 5600 – 4x

4x = 5200

(20)2 = 5600 – 4x

∴ 4x = 5600 – 400

∴ x = 1300

Hence, when x = 1300. then f(x) = 20.



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