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If f(x) = \(\frac{x^2−4}{x−2}\) where x ∈ Z – {2} then find the value of f(0) + f(1) – f(-2). |
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Answer» f(x) = \(\frac{x^2−4}{x−2}=\frac{(x+2)(x−2)}{x−2}\) = x + 2 ∴ f(0) + f(1) – f(-2) = (0 + 2 + (1 + 2) – (-2 + 2) = 2 + 3 – 0 = 5 |
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