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If `f :R ->R` , `f(x)=x^3 +3`,and `g:R->R`,`g(x)=2x + 1`, then `f^(-1)og^(-1)(23)` equalsA. 2B. 3C. `(14)^(1//3)`D. `(15)^(1//3)` |
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Answer» Correct Answer - A `f^(-1)og^(-1)(23)=(gof)^(-1)(23)` `"Now "gof(x)=2(x^(3)+3)+1` `"For "2(x^(3)+3)+1=23` `rArr" "x=2` `therefore" "gof^(-1)(23)=2` |
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