1.

If `f :R ->R` , `f(x)=x^3 +3`,and `g:R->R`,`g(x)=2x + 1`, then `f^(-1)og^(-1)(23)` equalsA. 2B. 3C. `(14)^(1//3)`D. `(15)^(1//3)`

Answer» Correct Answer - A
`f^(-1)og^(-1)(23)=(gof)^(-1)(23)`
`"Now "gof(x)=2(x^(3)+3)+1`
`"For "2(x^(3)+3)+1=23`
`rArr" "x=2`
`therefore" "gof^(-1)(23)=2`


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