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If `f: R ->R`is defined by `f(x) = x^2- 3x + 2`, find `f(f(x))`. |
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Answer» `f: R rarr R` and `f(x)=x^2-3x+2` `therefore f(f(x))=f(x^2-3x+2)` `(x^2-3x +2)^2-3(x^2-3x+2 )+2` `x^4+9x^2+4- 6x^3+4x^2-12 x - 3x^2+9x - 6 +2` `=x^4-6x^3+10 x^2-3x` |
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