1.

If f'(x) = 4x – 5 and f(2) = 1; find f(x)

Answer»

∫f'(x) dx = ∫(4x – 5) dx 

f(x) = 4x2/2 - 5x + c

f(x) = 2x2 – 5x + c 

But f(2) = 1 

2(2)2 – 5(2) + c = 1 

8 – 10 + c = 1 

c = 3 

Thus, f(x) = 2x2 – 5x + 3



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