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    				| 1. | ∫f(t) x∈[0,x] dt = x + ∫t f(t) x ∈[x,1] dt, then f(1) is equal to(a) 1/2(b) 0(c) 1(d) -1/2 | 
| Answer» Correct option (a) 1/2 Explanation: Differentiate both sides w.r.t x ⇒ f(x) = 1 + (0 - xf(x)) ⇒f(x) = 1/1 + x f(1) = 1/2 | |