1.

If f(x) = ax + bx + 2 and f(1) = 3, f(4) = 42,find a and b. 

Answer»

f(x) = ax2 + bx + 2

f(1) = 3

∴ a(1)2 + b(1) + 2 = 3

∴ a + b = 1 ….(i)

f(4) = 42

∴ a(4)2 + b(4) + 2 = 42

∴ 16a2 + 4b = 40

Dividing by 4, we get

4a + b = 10 …..(ii)

Solving (i) and (ii), we get

a = 3, b = -2



Discussion

No Comment Found