1.

If f(x) = \(\begin{cases}x^2+3,&x\leq2\\5x+7,&x>2\end{cases}\), x2 + 3, x ≤ 2, 5x + 7, x > 2, then find(i) f(3)(ii) f(2)(iii) f(0)

Answer»

f(x) = x2 + 3, x ≤ 2

= 5x + 7, x > 2

(i) f(3) = 5(3) + 7

= 15 + 7

= 22

(ii) f(2) = 22 + 3

= 4 + 3

 = 7

(iii) f(0) = 02 + 3 = 3



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