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If f(x) = \(\begin{cases}x^2+3,&x\leq2\\5x+7,&x>2\end{cases}\), x2 + 3, x ≤ 2, 5x + 7, x > 2, then find(i) f(3)(ii) f(2)(iii) f(0) |
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Answer» f(x) = x2 + 3, x ≤ 2 = 5x + 7, x > 2 (i) f(3) = 5(3) + 7 = 15 + 7 = 22 (ii) f(2) = 22 + 3 = 4 + 3 = 7 (iii) f(0) = 02 + 3 = 3 |
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