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If `f(x)=cos (logx)`, then `f(x)f(y)-1/2[f(x/y)+f(xy)]=` |
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Answer» Correct Answer - A We have, `f(x)=cos (log _(e) x)` `therefore f(x) f(y)-(1)/(2){f((x)/(y))+f(xy)}"` `=cos (log x) cos (log y)-(1)/(2){cos log((x)/(y))+cos (log (x y))}` `=cos (log x) cos (log y)-(1)/(2){cos (log-x log-y)+cos (log x+log y)}` `=cos (log x) cos (log y)-(1)/(2){2cos (log x) cos(log y)}` =0 |
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