InterviewSolution
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InterviewSolution
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If `f(x)` is a real-valued function defined as `f(x)=In (1-sinx),` then the graph of `f(x)` isA. symmetric about the line `x =pi`B. symmetric about the y-axisC. symmetric and the line ` x=(pi)/(2)`D. symmetric about the origin |
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Answer» Correct Answer - C `f((pi)/(2)-x)=In (1-cos x)` ` and f((pi)/(2)+x)=In(1-cosx)` Thus, `f((pi)/(2)+x)=f((pi)/(2)-x)` Thus f(x) is symmetrical about line `x=(pi)/(2).` |
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