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If `f(x)`is an invertible function and `g(x)=2f(x)+5,`then the value of `g^(-1)(x)i s``2f^(-1)(x)-5`(b) `1/(2f^(-1)(x)+5)``1/2f^(-1)(x)+5`(d) `f^(-1)((x-5)/2)`A. `2f^(-1)(x)-5`B. `(1)/(2f^(-1)(x)+5)`C. `(1)/(2)f^(-1)(x)+5`D. `f^(-1)((x-5)/(2))` |
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Answer» Correct Answer - D Given `g(x)=2f(x)+5` Replacing x by `g^(-1)(x)`, we get `g(g^(-1)(x))=2f(g^(-1)(x))+5` `rArr" "x=2 f(g^(-1)(x))+5` `rArr" "f(g^(-1)(x))=(x-5)/(2)` `rArr" "f^(-1)(x)=f^(-1)((x-5)/(2))` |
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