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If f(x) = sin [π2] x + sin [-π2] x, where [x] denotes the greatest integer less than or equal to x, then A. f (π/2) = 1 B. f(π) = 2 C. f (π/4) = - 1 D. None of these |
Answer» π2 ≈ 9.8596 [π2] = 9 and [-π2] = -10 Now, f(x) = sin[π2] x + sin[-π2]x = sin 9x - sin 10x Now, Checking values of f(x) at given points.. f(\(\frac{\pi}{2}\)) = sin 9(\(\frac{\pi}{2}\)) - sin 10(\(\frac{\pi}{2}\)) = 1-0 = 1 Option A is correct.. f(π) = sin 9π - sin 10π = 0 - 0 = 0 f(\(\frac{\pi}{4}\)) = sin 9(\(\frac{\pi}{4}\)) - sin 10(\(\frac{\pi}{4}\)) = \(\frac{1}{\sqrt 2}\) - 1 Option B & C are incorrect.. |
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