1.

If f (x) = singh e-k . Then pick correct option(s)(A) f' (0) = 0(B)T, (0) = f(0)(C) function has maxima at x = 0(D) function has minima at x = 0、// /-

Answer»

f(x) = sinx +e^(-x)

f'(x) = cosx +(-e^(-x) = cosx-e^(-x)f"(x) = -sinx +e^(-x) .

now f'(0) = 1-1 = 0

f(0) = 0+1 = 1 f"(0) = 0+1 = 1. ; so f"(0) = f(0)

for maximum and minimum valuef'(x) = 0.=> cosx-e^(-x) = 0=> cosx = e^(-x)only solution is x = 0.

so, this is the point of minima.



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