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If `f(x)=x^m n ,n in N ,`is an even function, then `m`iseven integer(b) odd integerany integer (d) `f(x)-e v e ni snotpos s i b l e`A. even integerB. odd integerC. any integerD. `f(x)`-even is not possible |
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Answer» Correct Answer - A Given `f(x)=sqrt(n)(x^(m)),n in N,` in an even function where `m in I`. So, `f(x)=f(-x)` `or root(n)(x^(m))=root(n)((-x)^(m))` ` or x^(m)=(-x)^(m)` i.e., m is an integer ` or m=2k, k in I` |
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