1.

If , find dy/dx.​

Answer»

ANSWER:

Step-by-step explanation:

GIVEN y=sinx^{cosx}

by log on both SIDES we GET

logy=cosx *logsinx

now DIFFRENTIATE with respect to x we get

1/y*dy/dx=cosx/sinx+logsinx(-sinx)

dy/dx= (cosx-sin^{2} xlogx)sinx^{cosx}/sinx

hope i answered the question



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