1.

If for a first order reaction, the values of A and E_a are 4 x 10^(13) sec^(-1) and 98.6 kJ/mol respectively, then at what temperature will its half-life period be 10 minutes?

Answer»

330 K
`33^(@)C`
`57^(@)`
311.15 K

Solution : ACCORDING to Arrhenius equation,`k=Ae^(-Ea//RT)`
log k =log A `-(E_a)/(2.303RT)`….(1)
For a FIRST order reaction,`t_(1//2)=(0.693)/(k)`
`t_(1//2)`=10min=600 s
`therefore k = (0.693)/(600)=1.1xx10^(-3)s^(-1)`…(2)
Putting value of k from eq. (2) in eq.(1) we get,
`log(1.1xx10^(-3))" "=" "log (4XX10^(13))-(98.6xx10^(3))/(2.303xx8.314xxT)
`therefore` T=311.15K


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