1.

If for a matrix A, `absA=6and adj A=`{:[(1,-2,4),(4,1,1),(-1,k,0)]:}`, then k is equal toA. -1B. 0C. 1D. 2

Answer» Correct Answer - B
If A is a square matrix of order `nxxn` then `abs(adjA)=abs(A)^(n-1)`.
Here, n =3,`absA=6and adjA={:[(1,-2,4),(4,1,1),(-1,k,0)]:}`.
`:. A={:abs((1,-2,4),(4,1,1),(-1,k,0))=6^2:}`
`-1,(-2-4)-k(1-36)rArr6+15k=36rArrk=2`


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