1.

If for Ag|Ag_((0.01M))^(+)||Ag_((0.1M)^(+)|Ag, cell E_(Ag^(+)|Ag)^(@)=0.80V, then . . .

Answer»

`E_(CELL)^(@)=0.80V`
`E_(cell)=0.0296V`
Cell will not WORK as both electrodes are same
`E_(cell)=0.059V`

Solution :`E_(cell)=E_(cell)^(@)-(0.059)/(n)"LOG"(0.01)/(0.1)`
`=-0.059xx(-1.0)`
`=0.059V`


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