1.

If for any given reaction if E_(cell)^(@) value is negative, then choose correct option for DeltaG^(@) and K.

Answer»

`DELTAG^(@) lt 0, K_(eq)gt1`
`DeltaG^(@) lt 0, K_(eq)lt1`
`DeltaG^(@) GT 0,K_(eq)lt1`
`DeltaG^(@) gt0,K_(eq)gt1`

Solution :`E_(cell)^(@)=-ve`
`DeltaG^(@)=-nF" "E_(cell)^(@)`
`DeltaG^(@)=+ve impliesDeltaG gt0`
`DeltaG^(@)=-2.303" RT "log" "K_(eq)`
`THEREFORE K_(eq) lt 1`


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