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If for hydrogen `C_(P) - C_(V) = m` and for nitrogen `C_(P) - C_(V) = n`, where `C_(P)` and `C_(V)` refer to specific heats per unit mass respectively at constant pressure and constant volume, the relation between `m` and `n` is (molecular weight of hydrogen = 2 and molecular weight or nitrogen = 14)A. `n = 14 m`B. `n = 7m`C. `m = 7n`D. `m = 14 n` |
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Answer» Correct Answer - C c.`C_(P) - C_(v) = m`, for hydrogen `(M_(1) = 2)` `C_(P) - C_(v) = n`, for nitrogen `(M_(2) = 14)` For hydrogen, `C_(P) - C_(v) = (1)/(M_(1)) (dQ)/(dT) = m` For nitrogen, `C_(P) - C_(v) = (1)/(M_(2)) (dQ)/(dT) = n` `:. (m)/(n) = ((1)/(M_(1)) (dQ)/(dT))/((1)/(M_(2)) (dQ)/(dT)) = (M_(2))/(M_(1)) = (14)/(2) = 7` `:. m = 7n` |
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