1.

If for the raction at 300 K, 2Mg(g)+O_(2)(g)to2MgO(s), Delta_(r)H=-1202kJ"mol"^(-1) and Delta_(r)S=-217.0JK^(-1)"mol"^(-1) The total entropy change (DeltaS)_(T) and gibbs energy change during the course of reaction (Delta_(r)G) are respectively.

Answer»

`3.79xx10^(3)JK^(-1)"mol"^(-1),-1136.9kJ`
`3.79xx10^(3)Jk^(-1)"mol"^(-1)+1000J`
`+1000JK^(-1)"mol"^(-1),3.79xx10^(3)J`
`-1136.9kJ, 3.79xx10^(3)J`

Solution :`DeltaG=DeltaH-TDeltaS`
`=-1202-(-217xx10^(-3)xx300)=-1136.9kJ`
Heat released will be ABSORBED by the SURROUNDING to increase the entropy of surroundings.
`DeltaS_("surr")=+(1202xx10^(3))/300=+4.01xx10^(3)JK^(-1)"mol"^(-1)`
`DeltaS_("TOTAL")=-217+4.01xx10^(3)=+3793JK^(-1)"mol"^(-1)`


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