1.

If force =(X)/(density)+C is dimensionally correct, the dimensions of X are :

Answer»

`MLT^(-2)`
`MLT^(-3)`
`ML^(2)T^(-3)`
`M^(2)L^(-2)T^(-2)`

Solution :Here FORCE has dimensions of `(X)/("density")`
`:.X=`Force `XX` density
or `X=[MLT^(-2)xxML^(-3)]`
`=[M^(2)L^(-2)T^(-2)]`
`:.(d)` is correct.


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