If \(\frac{4}{5}\),a, 2 are three consecutive terms of an A.P., then f

1.	If \(\frac{4}{5}\),a, 2 are three consecutive terms of an A.P., then find the value of a.
Answer» If \(\frac{4}{5}\),a, 2 are three terms in an A.P. so there common difference will be same a - 4/5 = 2 - a 2a = \(\frac{14}{5}\) a = \(\frac{7}{5}\) If a,b,c are three consecutive terms of an AP Then, \(b = {c + a \over 2}\) Thus \(a= {4/5 +2 \over 2}\) Ans: a=1.4 or 7/5

If \(\frac{4}{5}\),a, 2 are three consecutive terms of an A.P., then find the value of a.

Answer»

If \(\frac{4}{5}\),a, 2 are three terms in an A.P. so there common difference will be same

a - 4/5 = 2 - a

2a = \(\frac{14}{5}\)

a = \(\frac{7}{5}\)

If a,b,c are three consecutive terms of an AP

Then,

\(b = {c + a \over 2}\)

Thus \(a= {4/5 +2 \over 2}\)

Ans: a=1.4 or 7/5