If g is the transconductance and r is the resistance due to channel length modulation – what is the total voltage gain if both M2 and M3 has channel length modulation?(a) R/ ((1/g || r) + R) * g * (R || r) * R * g(b) R/ ((1/g + R) * g * (R || r) * R/ ((1/g || r) + R)(c) R/ ((1/g || r)) * g *R * R/ ((1/g || r) + R)(d) R/ ((1/g ) + R) * g *R * R *2gThe question was asked in final exam.My doubt is from MOSFET Amplifier with CD Configuration topic in portion FET Amplifiers of Analog Circuits

If g is the transconductance and r is the resistance due to channel le

1.	If g is the transconductance and r is the resistance due to channel length modulation – what is the total voltage gain if both M2 and M3 has channel length modulation?(a) R/ ((1/g \|\| r) + R) * g * (R \|\| r) * R * g(b) R/ ((1/g + R) * g * (R \|\| r) * R/ ((1/g \|\| r) + R)(c) R/ ((1/g \|\| r)) * g R R/ ((1/g \|\| r) + R)(d) R/ ((1/g ) + R) * g R R *2gThe question was asked in final exam.My doubt is from MOSFET Amplifier with CD Configuration topic in portion FET Amplifiers of Analog Circuits
Answer» Correct answer is (b) R/ ((1/g + R) * g * (R \|\| r) * R/ ((1/g \|\| r) + R) Explanation: This is a CASCADE of a follower stage follower by a CS stage which precedes another follower stage. The GAIN due to each stage gets multiplied until we reach the output. For the first stage, the gain is R / ((1/g+ R). The second stage has a gain of g * (R \|\| r)while the final stage has a gain of R/ ((1/g \|\| r) + R)- the effect of r is simply due to CHANNEL length modulation. After multiplying the GAINS, we get R/ ((1/g + R) * g * (R \|\| r) * R/ ((1/g \|\| r) + R).

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