1.

If g = t 2/3 + 4t -1/2, what is the value of g when t = 64?A. \(\cfrac{31}{2}\)B. \(\cfrac{33}{2}\)C. 16D. \(\cfrac{257}{16}\)

Answer»

g = t 2/3 + 4t -1/2 

= (64)2/3 + 4 (64) -1/2

= [(64)1/3] 3 + 4 \((\cfrac{1}{64})^\cfrac{1}{2}\)

= 42 + 4 (\(\cfrac{1}8\) )

= 16 + \(\cfrac{1}2\) = \(\cfrac{33}2\)



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