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If g = t 2/3 + 4t -1/2, what is the value of g when t = 64?A. \(\cfrac{31}{2}\)B. \(\cfrac{33}{2}\)C. 16D. \(\cfrac{257}{16}\) |
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Answer» g = t 2/3 + 4t -1/2 = (64)2/3 + 4 (64) -1/2 = [(64)1/3] 3 + 4 \((\cfrac{1}{64})^\cfrac{1}{2}\) = 42 + 4 (\(\cfrac{1}8\) ) = 16 + \(\cfrac{1}2\) = \(\cfrac{33}2\) |
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