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If `gamma` be the ratio of specific heats `(C_(p) & C_(v))` for a perfect gas. Find the number of degrees of freedom of a molecules of the gas? |
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Answer» Correct Answer - `(2)/(gamma-1)` `gamma = (C_(P))/(C_(V)) = (((f+2)/(2))R)/((f)/(2)R)` `= (f+2)/(f) =1+(2)/(f), f = (2)/(gamma-1)` |
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