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If `H_1.,H_2,…,H_20` are 20 harmonic means between 2 and 3, then `(H_1+2)/(H_1-2)+(H_20+3)/(H_20-3)=`A. 20B. 21C. 40D. 38 |
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Answer» Correct Answer - C `(H_(1)+2)/(H_(1)-2)+(H_(20)+3)/(H_(20)-3)=(1/2+1/H_(1))/(1/2-1/H_(1))+(1/3+1/H_(20))/(1/3-1/H_(20))` `=(1/2+1/2+d)/(1/2-d-1/2)+(1/3+1/3-d)/(1/3+d-1/3)` `=(1+d)/(-d)+(2/3-d)/d` `=(2/3-1)/d-2` `=2xx21-2` [as also,`1/3=1/2+21d`] =40 |
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