If H_2(g)+Cl_2(g)→2HCl, ^@=-44 kcal 2Na(s)+2HCl(g→)2NaCl(s)+H_2(g – InterviewSolution

1.	If H_2(g)+Cl_2(g)→2HCl, ^@=-44 kcal 2Na(s)+2HCl(g→)2NaCl(s)+H_2(g), △H =-152 kcalthen, Na(s)+0.5Cl_2(g)→NaCl(s),△H =?
Answer» 108 KCAL 196 kcal `-98 kcal` 54 kcal Answer :B

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