1.

If H_(n) = 1+ (1)/(2) + (1)/(3) + …. + (1)/( n) , AA n in N, then H_(1) + H_(2) + H_(3)+ …. + H_(n) =

Answer»

`(N+1)H_(n) -n`
`(n+1) H_(n) +n`
`(n+1) H_(n)`
`(n-1) H_(n) -n`

ANSWER :A


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