1.

If H(s)=\(\frac{1}{s^2+s+1}\) represent the transfer function of a low pass filter (not Butterworth) with a pass band of 1 rad/sec, then what is the system function of a high pass filter with a cutoff frequency of 10 rad/sec?(a) \(\frac{100}{s^2+10s+100}\)(b) \(\frac{s^2}{s^2+s+1}\)(c) \(\frac{s^2}{s^2+10s+100}\)(d) None of the mentionedThis question was addressed to me during an internship interview.My question is from Design of Low Pass Butterworth Filters in portion Digital Filters Design of Digital Signal Processing

Answer»

The CORRECT OPTION is (C) \(\FRAC{s^2}{s^2+10s+100}\)

Best explanation: The low pass-to-high pass transformation is

s→Ωu/s

Hence the required low pass filter is

Ha(s)=H(s)|s→10/s

=\(\frac{s^2}{s^2+10s+100}\)



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