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If half power beam width in one plane and other plane orthogonal to it are equal to π then the directivity is ____(a) π(b) 4π(c) 4/π(d) 2πThis question was addressed to me in an interview for job.Question is from Directivity topic in section Antenna Parameters of Antennas

Answer»

The correct OPTION is (c) 4/π

The best I can explain: BEAM AREA ΩA≈ θ1r θ2rwhere θ1r, θ2r are half-power beam widths in radians.

Directivity \(D=\frac{4\pi}{\Omega_A}=\frac{4\pi}{\theta_{1R}\theta_{2r}}=\frac{4\pi}{\pi.\pi} = 4/\pi\)



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