InterviewSolution
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InterviewSolution
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If he line drawn from the point `(-2,-1,-3)`meets a plane at right angle at the point `(1,-3,3),`find the equation of the plane. |
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Answer» Since the line drawn from the point `(-2,-1,-3)` meets a plane at right angle at the point `(1,-3,3)`. So the plane passes through the point `(1,-3,3)` and normal to plane is `(-3hati+2hatj-5hatk)` ltrbgt `implies veca=hati-3hatj+3hatk` and `vecN=-3hati+2hatj-6hatk` So the equation of required plane is `(vecr-veca).vecN=0` `implies[(xhati+yhatj+zhatk)-(hati-3hatj+3hatk)].(-3hatk+2hatj-6hatk)=0` `implies [(x-1)hati+(y+3)hatj+(z-3)hatk].(-3hati+2hatj-6hatk)=0` `implies -3x+3+2y+6-6z+18=0` `implies -3x+2y-6z=-27` `:. 3x-2y+6z-27=0` |
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