1.

If I.E. of Na, Mg and Si are respectively 496, 737 and 786 kJ "mol"^(-)The I.E. of Al in KJ "mol"^(-) is :-

Answer»

575
760
390
1120

Solution :`underset(3S^(-1))(Na) lt underset(3s^(2))(Mg) gt underset(3s^(2)3p^(1))(Al) lt underset(3s^(2)3p^(2))(Si)`
Sequential ORDER`to underset(786)(Si ) gt underset(737) (Mg) gt underset (575)(Al) gt underset(496)(Na)`


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