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If identical charges `(-q)` are placed at each corner of a cube of side `b`, then electric potential energy of charge `(+q)` which is palced at centre of the cube will beA. `(8sqrt(2)q^(2))/(4pi epsilon_(0)b)`B. `(-8sqrt(2)q^(2))/(pi epsilon_(0)b)`C. `(-4sqrt(2)q^(2))/(pi epsilon_(0)b)`D. `(-4sqrt(2)q^(2))/(sqrt(3)pi epsilon_(0)b)` |
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Answer» Correct Answer - D Length of the diagonal of a cube having each side `b` is `sqrt(3)b`. So distance of centre of cube from each vertex is `(sqrt(3) b)/(2)`. Hence potential, energy of the given system of change is `U = 8 xx {(1)/(4pi epsilon_(0)).((-q)(q))/(sqrt(3)b//2)} = (-4q^(2))/(sqrt(3) pi epsilon_(0)b)` |
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