1.

If in a ∆ABC, tan A + tan B + tan C = 6, then cot A cot B cot C = A. 6 B. 1 C. 1/6 D. None of these

Answer»

A + B = π - C

\(\frac{tanA+tanB}{1-tanAtanB}\) = - tan c

tan A + tan B + tan C = tanA tanB tanC

cot A cot B cot C = \(\frac{1}6\)



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