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If in a ∆ABC, tan A + tan B + tan C = 6, then cot A cot B cot C = A. 6 B. 1 C. 1/6 D. None of these |
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Answer» A + B = π - C \(\frac{tanA+tanB}{1-tanAtanB}\) = - tan c tan A + tan B + tan C = tanA tanB tanC cot A cot B cot C = \(\frac{1}6\) |
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