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If in a triangle a `cos^2C/2+cos^2A/2=(3b)/2,`then find the relation between the sides of the triangle. |
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Answer» `a cos^(2).(C)/(2) + cos^(2).(A)/(2) = (3b)/(2)` or `a (1 + cos C) + c (1 + cos A) = 3b` or `a+c + (a cos C + c cos A) = 3b` or `a + c + b = 3b` [bt the projection formula] or `a + c = 2b` Hence, a, b, c and in A.P. |
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