1.

If in an AP, 8th term is 4 and 16th term is -20, then find the common difference of the given AP.​

Answer»

Given :

  • If in an AP, 8th term is 4 and 16th term is -20 .

To Find :

Solution :

As Given that ,

\longmapsto\tt{a+7d=4}

\longmapsto\tt{a+15d=-20}

Now By Elimination Method :

\longmapsto\tt{{\not{a}}+7d=4}

\longmapsto\tt{{\not{a}}+15d=-20}

\longmapsto\tt{-8d=24}

\longmapsto\tt{d=\cancel\dfrac{24}{-8}}

\longmapsto\tt\bf{d=-<klux>3</klux>}

So , The Common Difference of the given A.P is -3 .

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  • {a}_{n}=a + (n-1) × d
  • General FORM = a , a + d , a + 2d ...
  • s = n/2 [2a (n-1) × d]

Here :

  • n = nth term
  • a = FIRST term of the a.p
  • s = SUM of nth terms
  • d = common difference

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