1.

If in diamond there is a unit cell of carbon atoms as fcc and if carbon atom is sp^(3) hybridised, what fractions of voids are occupied by carbon atom?

Answer»

0.25
tetrahedral
50% tetrahedral
25% octahderal

Solution :`sp^(3)` hybbridised C-atom suggest a tetrahddral arrangement of 4 C-atoms. For fcc number of atoms (N) PER UNIT cell =4
`:.` Total available tetrahedral voidds `=2N=2xx4=8`
Occupied tetrahedral VOID `=4` i.e 50% of the total.


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