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If in the fementation of sugar in an enzymatic solution thatis 0.12m the concentration of the sugar is reduced to 0.06m in 10h and to 0.03m in 20h. What is the order of reaction |
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Answer» SOLUTION :`1` `0.12m to 0.06m`, `50%`, CHANGE `t_(1//2)=10H` `0.12m to 0.03m`, `75%`, change `t_(3/4)=20h` Since `t_(3//4)=2xxt_(1//2)`. Hence order is `1` |
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